Opamp with RLC in parallel and load
Frequency = 1
___________________________________
iL=inductor current
R2 is parallel with LC
choose iL
choos R2
choose Vout
And you find q (q must be less than 1 to get a perfect sine wave)
q=Vout*w/2*R2*iL
L=2*R2*q/w^2
w=2*pi*frequency
C=1/w^2*L
Vs=square wave amplitude
R1=Vs*w*0.636*0.707/2*q*iL
i(in)= Vs*0.636*0.707/R1
