Simulated Inverter for Active Low Output

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Normally, a chip with an active LOW output would send a HIGH until triggered, thus if the intent was to turn an LED on only when a specific input was triggered, an inverter (NOT gate) would be required, followed by an LED with a resistor and ground.  In this demonstration, the LED is reversed and a positive voltage is applied where the ground was.  This way, the float HIGH leaving a chip would be negated by the +5V coming across the LED.  Once the chip goes LOW, current can flow through the LED.

published 4 years ago

lensrulz

4 years ago

👍

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