Driver led protection to 8V_ 100V

The led is rated for 20ma and 2v. Adjust each resistor and the mosfet settings for both current and voltage control.

Oh, @wyoelk, careful or you’ll have hurz call you a charlatan. But I support using 20mA since the EC default is 20mA. Nonetheless he is rightly pointing out than in reality less current is required. Sadly he cannot seem to do this without attacking people.

Since most of us are or should or could be considered newbies or definitely short on knowledge and experience, it seems appropriate to consult the app developers as follows: When designing circuits with light-emitting diodes (LED), the primary concern is that too much current and voltage may damage the LED. The simplest way to protect an LED is to include a current limiting resistor in series. LEDs have recommended operating voltage and current, based on which you can calculate the resistance using Kirchhoff's laws. EveryCircuit makes it super-easy to find the right resistance value. Launch simulation and plot LED voltage and current in oscilloscope. Then tune the resistance with the knob until LED voltage and current are optimal. LED lights up when it has enough current. It also indicates when the current exceeds the nominal by over 2x.

@wyoelk, you continues talking about a current limiting resistor. You missed the fact here we have a constant current sink which does not need an extra resistor! there is a shunt resistor 20.8Ohm and a working pullup resistor to transform current into the mosfet needed voltage. This LED here is totaly current driven! BTW, you mix voltage and current to quickly. Think of only in current when talking about LEDs If the voltage is above its limits its also the current. and if the current is to low its also the voltage. Again, here the resistora are not current limiting resistor directly for the LED they have a job as !Constant Current Sink!