Who can guess the code

23 or 29 depending on how you look at it.

Nope it's a trick question, a wild goose chase- the LED is to be turned on by an AND gate, requiring both inputs to be high to give a strong enough signal out. However one of the inputs to that AND gate is also tied to an inverter, which will output low if the switch is high. But we need the inverter to output high for the next sequence to output high, so the switch would have to be low but we need it to be high for the AND gate to output high so we'll light the LED! So like I said- a wild goose chase..

Wait, scratch that! I got it.. X^)

@Jamey-It is 2^5=32 combinations. 2choices(+ or -) to the power of 5bits/inputs = 2^5 = 32combinations, Choices(2) ^ Bits/inputs(5) = Combinations(32). @Sine_eyed-You have to find the way of the logic(universal logic theory will help).

No I said I got it. If the led comes on then I got it, correct? not just going to say the answer though..

I didn't expect anyone to create a little mini-game within everycircuit. Neat though (and yes, I solved it)

1+2+4+16 or 1+4+8+16 is what @jamey already said

Got it

Awesome job @Voltransistor, oh but why tax us old gray matter so....made me use my abacus and slide rule

1-1-1-0-1

@ik-Dang it! You one! @wyoelk-Thankyou! Lol.

That was cool wow you are very talent thank's

>=^(] nope, no sorry, Voltran if you're gonna call a winner it better be me. Yep, that's right- sorry @ik don't mean to swipe the glory but, it was me. I saw it first, I said it first, I solved it first. I'm first- me. Right here. Numero uno. Why am I dancing you ask? Because I won. Winner- came in the top spot. Yep. Voltran, if you would be so kind- verify that I am truly by all accounts and measures the... wait for it...... WINNER of your most awesome logic puzzle. You can do so by checking the street lamp circuit you posted recently- I replied there with the winning combination just to make it all legal like. Thanks Voltran it was fun- and uh, please let everyone know of your findings yeah?..