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Chote
modified 9 years ago

Simple led

2
1
77
02:31:14
Led
published 9 years ago
ViVBling
9 years ago
To get 20㎃ flowing through an LED (2V, 20㎃) at 34,2V you need a 1.610Ω resistor. A simple calculation shows the result: (34,2V − 2V) ÷ 20㎃ = 1.610Ω

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