If you want to do this circuit,
Vs = T *Ve = [K+(2*K²/k0)] * Ve
-> The reference value of the resistors is 10k ohms (there is 2 reistors at 10k ohms, we need to never touch them)
-> K = 2 here. For this example, there is 4 reistors that are concerned if you want to modify K (their values are K*10k = 2*10k = 20k ohms)
-> k0 = 4 here. It is the extern resistor, here his value = 4*10k = 40k ohms
-> Finally, with thoses values,
Vs = 2+(2*2²/4) * 1V = 4V
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And if you want to use a real AD620 (the integrated component). You will see that his Gain Gad620 is defined by G=1+(49400/Rext)
You probabliy want to have the Gain of AD620 as the gain T = [K+(2*K²/k0)].
Turn the formula and get
Rext = 49400/(Gad620)-1
Rext = 49400/(K+(2*K²/k0))-1
