AD620

If you want to do this circuit, Vs = T *Ve = [K+(2*K²/k0)] * Ve -> The reference value of the resistors is 10k ohms (there is 2 reistors at 10k ohms, we need to never touch them) -> K = 2 here. For this example, there is 4 reistors that are concerned if you want to modify K (their values are K*10k = 2*10k = 20k ohms) -> k0 = 4 here. It is the extern resistor, here his value = 4*10k = 40k ohms -> Finally, with thoses values, Vs = 2+(2*2²/4) * 1V = 4V --------------------------------------------------------- And if you want to use a real AD620 (the integrated component). You will see that his Gain Gad620 is defined by G=1+(49400/Rext) You probabliy want to have the Gain of AD620 as the gain T = [K+(2*K²/k0)]. Turn the formula and get Rext = 49400/(Gad620)-1 Rext = 49400/(K+(2*K²/k0))-1

published 11 months ago