modified 10 years ago

capacitors in parallel

01:17:12

when the capacitors are in parallel the capacitance increase and the voltage remain the same of each one as the total voltage of a power supply

to find the total capacitance in a parallel circuit you just have to sum each capacitors

Ct= 3µF+6µF+9µF= CT= 18µF

to find total charge stole Qt?

Qt=(Ct)(Vt)
Qt=(18µF)(9v) = Qt= 162 coulombs of total charge

to find the voltage?
the voltage of each capacitors is equal to the foltage of the power supply

C1,C2 and C3= total of power 9 volts all capacitors have nine volts passing thru them.

all of this circuit is create by Jenko022 on via youtube

published 10 years ago

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