PURE digital

164

02:19:58

It is a analog wave to digital wave. Thankyou for the solution, Hurz. :-) I'm trying to help Fowl77 Of a analog to digital converter. It uses a positive feedback for an absolute digital converter. It is efficient from the 5kΩ resistor to amplify with two transistors to the output. I changed it, so there is no pointless positive input feedback and I made an extra transistor to turn the output back "off"(inverter) mainly every inverter makes it higher of a digital funtion. 

published 11 years ago

hurz

11 years ago

Why this opamp with positive feedback, this will cause infinite rising edges and histeresis which lets the circuit freeze. Just put one end at ground and your opamp works as comparator - which is what i guess you want, an analoge to digital converter.

Voltransistor

11 years ago

Thankyou, Hurz! I'll try to do that. :-)

hurz

11 years ago

This is much better, but the 100k can not have any effect because any ac source does have 0 ohm internal resistance. So you dont get an hysteresis. You need a little serial resistance from AC to plus input. Like the way you help him. Keep it up!

Voltransistor

11 years ago

Thankyou!

hurz

11 years ago

One more tipp, reverse logic by swap comparator inputs ;-) So you do not need an extra transistor

Voltransistor

11 years ago

True, but it does prove 95% of the wave is digital, which means its only 5% slanted. I've always thought a 100% digital wave takes a latch(set and reset) to make the digital wave 100%, so I tried to make it one more step closest to perfect. For example is a square has to be a perfect 90° angle on every side to make it a square, not a trapizoid or a parallelagram.

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