Calculating the Capacitance between parallel and series capacitors in a circuit.

Every circuit app doesn't have a DPDT switch so I used two relays in parallel. Hold and release switch (push button NO) to charge and discharge both of the capacitors in parallel and series. The discharge time of circuit 1 in parallel and circuit 2 in series is the same even though the values ​ ​ are different .Why? "CAPACITORS IN PARALLEL" Connecting capacitors in parallel, increases the area that is exposed to each conductor. Simple addition of the values will give the resulting capacity. Remember, the working voltage rating will be the lowest rating of any one of the capacitors. Tolal Capacitance in parallel is C1+C2+C3 2uf+2uf+2uf = 6uf "CAPACITORS IN SERIES" In this case, you are actually separating the top plate of C4 and the lower plate of C6. This will reduce the capacitance. How much less? Less than the lowest-capacity capacitor in the series. This is because the amount of charge that can be stored between the lower plate of C6 and the upper plate of C4 depends on the capacity of those conductors (plates) in between. Total Capacitance in series is ____________1____________ ___1___+____1___+___1____ C4 C5 C6 ____________1____________ ___1___+____1___+___1____ =____3____ = ____1___ or 6uf 18uf 18uf 18uf 18uf 6uf Correct me if I'm wrong thanks 🙏 Just for sharing...😘

published 3 years ago