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Logarithmic Amplifier

@yashgumaste
10 years ago
https://everycircuit.com/circuit/6113143271981056
Vo = -nVt (ln (Vin/R1) - ln Io) Vo - Output voltage n - Intrinsic semiconductor rate Vt - Thermal equivalent of voltage = 26mV ln - log to base e Vin - Input voltage R1 - Input series resistance = 1Kohm Io = leakage current of diode Vo is proportional to ln (Vin/R1) Output is proportional to logarithmic of input. Therefore the name Logarithmic Amplifier
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