test led

142

02:03:31

W

published 1 year ago

EricsElectronicAdventures

1 year ago

The LED has 73.2 Amps through it. (Hence the flames) You need a current limiting resistor. With a 2V drop across the LED and a 6V source, that leaves 4V for the resistor. The diode should be limited to 20mA. So 4V÷0.020mA=200Ohms. Add a 200 ohm resistor in series with the LED.

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