Vin = 1v at open circuit
R1 = 1k
R2 = 1k
Rload = 1k
Press and hold the button to find out the I-thev.
Vth = Vin*(R2/(R1+R2))
Vth = 900/1900=0.526V
So then let's get R-thev
Rth = Vth/Ith
Rth = 0.526v/1.11mA = 474 Ohm
So then if we apply a load parallel to R2 it will behave exactly as if we'd connect or in series with our Rthev.
And it is! Both circuits show usage of 213uA.
Hooray!
