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DayDreamer
modified 7 years ago

AoE 1.12 Thevenin equivalent of a voltage divider.

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01:15:11
Vin = 1v at open circuit R1 = 1k R2 = 1k Rload = 1k Press and hold the button to find out the I-thev. Vth = Vin*(R2/(R1+R2)) Vth = 900/1900=0.526V So then let's get R-thev Rth = Vth/Ith Rth = 0.526v/1.11mA = 474 Ohm So then if we apply a load parallel to R2 it will behave exactly as if we'd connect or in series with our Rthev. And it is! Both circuits show usage of 213uA. Hooray!
published 7 years ago

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