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BraydanD
modified 0 year ago

RF Power Amp

1
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174
02:52:26
Biased using a 500uA current source for 50mA of collector current through the power transitor. Using a 133pF coupling capacitor for ensuring an output impedance of 50 ohms to perfectly match a 50 ohm load. Each LC filter component has a reactance of 50 ohms at the desired frequency, again to ensure max power transfer. The output power is: Vrms^2 / 50 = 3.06V^2 / 50 = 187.3 mW or 22.725 dBm Decreasing the current mirror's resistor from 16.5k to 2.2k, you can really crank up the output power to 1W.
published 0 year ago

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