how to find the current when we have two resistor in series and two siloconddiode in series

We have to add the voltage value from the two diode that will be 1.4volt we subtract the power source voltage of 10vol minus 1.4volt= 8.6volt then we add the total resistance in series that is 3.3kohms so now we use the ohms formula of current I= V/R I= 8.6v/ 3.3kohms l= 2.60mA