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dB7
modified 3 months ago

Why Capacitor produces negative voltage

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01:35:06
When you hold the button, the node between capacitor and resistor in series with it, starts at 5V, then goes to 0V when button is pressed. When button released, voltage at that node jumps to around -2V. I don't understand how and why it goes negative. Also when I decrease resistor in first branch to 20ohm, then voltage drops more to -4V. I don't get it please someone help
published 3 months ago
Teteh49680
3 months ago
Because the two resistor are in parallel and act like a Resistive Pontencial Divider. Sou you get half of voltage, because they have the same value. Vout=(R2/(R1+R2))*Vin
Unwinroad03
3 months ago
At 1st i thought the voltage Drop was caused by capacitors 63% discharge and then ramps up but never reaches 0v. But if you Go back three nodes you'll see voltage drops to about 2.3V then gradually gets depleted. IDK sorry

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