ohms law resistors in series

what is resistor? reduce the flow of current in a circuit Series Circuit is used to increase the resistance (5+7+10) Rt=22ohms ( reduce the voltage) the voltage drops as pass over each resistors starts with 24v then 18.5 then 10.9v then 0v and start again voltage drops as pass over each resistor the current which is 1.09 amps is multiply by the first Resistor with 5 ohms = 5.45 so we subtract the volt of 24v minus 5.45 from the resistor and the current and we get the voltage of 18.5 voltage then 1.09 amps multiply by R2 7 ohms equal 7.63 volts minus 18.5v = 10.9 volt then 1.09 amps multiply by R3 10 ohms = 10.9 minus 10.9 volt = 0 volt if we sum 5.45 volt + 7.63 volt + 10.9 volt = 24 volt of power supply voltage keep the current at the same level R1= current is 1.09amps R2=current is 1.09amps R3= current is 1.09amps 24v/22ohms= total current of the circuitis is the same (It= 1.09amps) All of this circuit is create by Jenko022 on via youtube

published 10 years ago