modified 3 years ago

Are Amp Sources Immune to Ohm’s Law

00:32:09

What am I missing here?

published 3 years ago

nordistu

3 years ago

I guess you are missing the internal resistence of a constant current source

592azy2circuitdude

3 years ago

I'm sure that current sources follow ohms law. A perfect current source will push a constant current through the load resistance. That means it will produce the necessary voltage given by ohms law V = I × R.

592azy2circuitdude

3 years ago

In your example, the load resistances are the 1ohm resistor + the 1ohm LED. So the current is 1amp and resistance is 2ohms. Therefore the voltage across the current source is V = 1 × 2 = 2V. The voltage across the LED is V = 1 × 1 = 1V. You can see these values in the circuit.

592azy2circuitdude

3 years ago

I hope this helps. Good luck 👍

timmyboymedia

3 years ago

Thanks everyone!

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