Transformerless Power Supply and Linear Regulator

234

03:11:16

Transformer-less mains power supply and a linear regulator circuit. Output voltage can be changed by calculating a R1 = ((Vout x 1000)/(2.4)) - 1000

published 7 years ago

jason9

7 years ago

Linear regulators are very inefficient. The design you have set up here will draw ten times as much power as it produces causing it to dissipate way more power than it generated useful power.

YoussefAly97

7 years ago

@jason9 well that's true from an electrical power engineer's point of view, in an electronics/communications engineer point of view, linear regulators are perfect for supplying noise sensitive devices. Usually a switching pre regulator is used then a linear one after that to get decent ripple rejection.

hurz

7 years ago

The factor 2.4 is more 2.3 cuz you do not drive the zener close to 13.6mA which is the current for EC exact zener voltage.

hurz

7 years ago

BTW, why haven't you tested this circuit, or did you?

YoussefAly97

7 years ago

@hurz, I'm not sure what you mean by EC exact zener voltage and I know the 2.4 neglects the calculation of the zener reference voltage. Do you mean test it in real life? If so, I have yet to test it, looking into designing one that outputs 3.3v 500 mA first.

hurz

7 years ago

No, first i mean testing here in EC, cuz the regulator (lower part of worksheet circuit) gets its voltage from ground by a switch from upper part! At least this has to be changed

hurz

7 years ago

For the perfect zener current, you can get any voltage from 0V till a little above zener voltage by tuning the current. Everycircuit zener give you the nominal rated voltage at exact 13.6mA doesn't matter what the zener voltage is!

hurz

7 years ago

BTW, you know what you are doing at mains voltage?

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