8 bit Digital to Analog Converter

151

02:06:24

published 11 years ago

hurz

11 years ago

In theorie, yes! But as a pratical one, no. E.g. 1k||128k = 992Ohm ! Which lefts just 0.8% room (normal resistors may have 1%) and 0.8% is even very optimistic you need even <0.4%. Or see it this way 2^8=256 to meet at least this you need 9 bit precision 2^9=512 -> 0.2%!!! Happy calibrating, and dont forget the temperatur coefficient ;-)

Ballphilipp

11 years ago

Perfect

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