modified 4 years ago

HW4_Khalid Alsadoon_2138670_Section06

00:14:16

Third circuit

Power of the resistor
P = (12V)^2 / 300Ω = 0.48W
P = 12V * 0.032A ≈ 0.38W
P = (0.032A)^2 * 300 ≈ 0.31W

Power of the lightbulb 
P = (2.4V)^2 / 300Ω = 0.02W
P = 2.4V * 0.032A ≈ 0.08W
P = (0.032A)^2 * 300Ω ≈ 0.31W

Please inform me if there are any mistakes and also I want to know why am I getting different values of the power for each component?

published 4 years ago

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