Spike generator

113

01:25:11

Why the output voltage is quite low??

published 11 years ago

orhun

11 years ago

The output voltage should have been 0V at all times. However since there is a transition time for digital input, there is a short time where both the inputs for And gate is both (almost) high. This makes the output also "high". Since the transition time is short, the output cannot reach 5V. Thats my little guess :)

kaivanveldhoven

11 years ago

Because the pulse generator's rising edge has a slope to it, theres a little point in time in which both terminals of the and gate are high, before the invertor stops this.

kaivanveldhoven

11 years ago

Perfect explanation orhun! :)

northernpeso

11 years ago

This spike is due to the propogation delay of the inverter.

wpropati

11 years ago

The spike is not caused by the propagation delay. It has to do with the transition times, as Orhan said. Change the rise and fall times to 0% and it almost completely goes away. Then you have a tiny spike the size of a few millivolts. That extremely small spike would be the propagation.

transamplifier

11 years ago

Yes..correct..@wpropati

hurz

11 years ago

Hey guys, you are on the wrong track. It doesn't have to do with timing. Its the different transfer function of NOT gate and AND gate. Vout(Vin) of AND is a little asymetric while the NOT is perfectly symetric. Hope this helps.

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