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Saya2001
modified 9 years ago

Power transmission line

7
10
246
03:04:18
Power transmission line from power generating stations to the city consumers Step 1 Power is generated at 11kV 50Hz Step 2 The voltage is stepped up to 132kV using a step up transformer. This is because for a given power, greater the voltage, lesser is the current flowing through the wire (P=VI) and lesser current means less loss power due to heating effect ( H=I²Rt). Step 3 Voltage is stepped down from 132kV to 33kV . Some of it is used by heavy industries. Step 4 33kV is stepped down to 11kV and some of it is used by light industries Step 5 11kV is stepped down to 220V for city consumers. The above circuit shows the steps in power transmission line. The yellow and red switches symbolize heavy and light industries respectively. Summing up 11kV AC to 132kV AC to 33kV AC to 11kV AC to 220V AC
published 9 years ago
hurz
9 years ago
Guess what https://en.m.wikipedia.org/wiki/Root_mean_square
Saya2001
9 years ago
Did you like it?
hurz
9 years ago
Have you read it?
Saya2001
9 years ago
I have read it but did not understand anything
hurz
9 years ago
Check this, it might help you to understand http://everycircuit.com/circuit/4699420976742400
hurz
9 years ago
So what is the correct peak voltage for 11kVAC?
Saya2001
9 years ago
11kV AC is the peak only while the DC Voltage is 7778.17V
rich11292000
9 years ago
Your output is 220v peak. It needs to be 220v rms. 220x1.414=311v peak. The value of voltage is rated in rms.
rich11292000
9 years ago
Imagine a resistor to make a heater. Apply 1VDC, then measure max heat output. Then apply 1.414VAC "PEAK" then measure max heat output. The DC heater will produce the same heat that the AC heater produces, they will also consume the same wattage. This 1.414VAC "PEAK" is the same (force/pressure) as 1VDC. So for 11kVAC (11kVAC "RMS") we need to multiple the rms value by 1.414. 11x1.414=15.55kVAC"PEAK".
Saya2001
9 years ago
Yes

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