240v 10k resistor three leds

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01:49:31

I  was trying to work out why a 10k resistor in a bridge rectifier was dropping the voltage of 240v down to 7v https://everycircuit.com/circuit/6565876587036672 and was a bit stuck .

So simplifying the problem  I have removed the AC power and bridge rectifier and am left with 240v DC  a resistor and two diodes.     

Pushing the  figures through a resistor calculator   https://www.hobby-hour.com/electronics/ledcalc.php  240v  led current 23.2ma 2v drop 3 leds in series  (push calculate) and I get  10kohms.

V=IR     R = V/I
voltage drop is approx 8 volts
R = (240-8)/.023 = 10087 ohms 

published 4 years ago

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