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m8965max
modified 10 years ago

Parallel source

5
9
177
03:55:38
Why is it short i dont understand if i want to raise current but voltage remain the same parallel is the answer right.
published 10 years ago
BillyT
10 years ago
By Ohms Law to raise the current, you have to either raise the voltage or lower the resistance of the lightbulb, you could put a second lamp in parallel with the other one.
wyoelk
10 years ago
Put the batteries in series not parallel if you need two batteries
m8965max
10 years ago
I dont need more volts just more current
Meilleur
10 years ago
If you built such a device, extra power sources in parallel will add current. For this program, you will want to add a diode in series with each power source to avoid the error message.
Meilleur
10 years ago
Also, this app will not show the extra current regardless of how many power sources you add.
m8965max
10 years ago
Thanks alot
MosfetSpaceport
10 years ago
Actually, it will show the extra current using the ammeter symbol. Since the power-source is infinite, current values are only determined by the load. By adding 2 diodes and an ammeter, it shows a total current of 31.8mA, split evenly across the power-supplies and the lightbulbs.
rich11292000
10 years ago
Batteries have internal resistance. The ideal sources have zero resistance. You cant add ideal sources in parallel because of zero resistance.
ksviveksiddarth
10 years ago
rich11292000 is right . Just add 1 milli ohm resistor to the source and check

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