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m8965max
modified 9 years ago

Parallel source

5
9
176
03:55:31
Why is it short i dont understand if i want to raise current but voltage remain the same parallel is the answer right.
published 9 years ago
BillyT
9 years ago
By Ohms Law to raise the current, you have to either raise the voltage or lower the resistance of the lightbulb, you could put a second lamp in parallel with the other one.
wyoelk
9 years ago
Put the batteries in series not parallel if you need two batteries
m8965max
9 years ago
I dont need more volts just more current
Meilleur
9 years ago
If you built such a device, extra power sources in parallel will add current. For this program, you will want to add a diode in series with each power source to avoid the error message.
Meilleur
9 years ago
Also, this app will not show the extra current regardless of how many power sources you add.
m8965max
9 years ago
Thanks alot
MosfetSpaceport
9 years ago
Actually, it will show the extra current using the ammeter symbol. Since the power-source is infinite, current values are only determined by the load. By adding 2 diodes and an ammeter, it shows a total current of 31.8mA, split evenly across the power-supplies and the lightbulbs.
rich11292000
9 years ago
Batteries have internal resistance. The ideal sources have zero resistance. You cant add ideal sources in parallel because of zero resistance.
ksviveksiddarth
9 years ago
rich11292000 is right . Just add 1 milli ohm resistor to the source and check

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