Relay

219

03:52:14

Basic Relay Circuit

published 4 years ago

Redstone_guy

4 years ago

You need to connect one pin of each and every voltage source to ground

wyoelk

4 years ago

Like this one http://everycircuit.com/circuit/6668370968313856

Redstone_guy

4 years ago

@Electrical_Professor, being incandescent lamps, the voltage polarity applied to them is not relevant, but personally, I don't use positive ground much. Also, if a voltage source is to emit, well, any voltage, it MUST have ONE pin connected to common ground. Connecting BOTH pins to ground will obviously create a short circuit, where things can only go downhill... 💥💥💥💥

Redstone_guy

4 years ago

Thus, pressing the button will not cause the relay contacts to switch, because current cannot flow through the coil, for the voltage source is not connected to common ground

sean1401032

4 years ago

@Redstone_guy, surely this is a trivial matter of the circuit simulator refusing to deal with floating values. One could reproduce this circuit in the flesh and would not need to make any form of reference between the two galvanically isolated sides of the transformer to ground. The voltage source produces a potential between its two sides regardless of reference to any form of ground and would still create the necessary switching current in the primary. Please correct me if I am wrong!

Richardc

4 years ago

@sean1401032 you are correct, the use of a ground pin is only required by the simulator.

BillyT

4 years ago

Try this circuit for closer to correct values, http://everycircuit.com/circuit/6251467851431936

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