modified 10 years ago

ohms law Resistors in Parallel

01:15:32

Parallel Circuit 

is used to decrease the resistance 
(1/6+1/3+1/8)-1= Rt 1.6kohms

         (reduce the current )

depending of the amount of resistance the current drop 

R1 current is 2.5 mamps
R2 current is 5 mamps
R3 current is 1.88 mamps

total current= V 15 volt / Rt 1.6 k ohms = 
 ( It = 9.38 amps ) 
R1 2.5amps +R2 5 amps +R3 7.98 amps

keep the voltage at the same level Vt=15volt

all of this circuit is create by Jenko022 on via youtube

published 10 years ago

Lucan01

10 years ago

***keep the voltage at the same level vt=15kV. ***

Lucan01

10 years ago

Thanks for sharing

williamdoel

10 years ago

you welcome

SantoshkumarMahto

1 year ago

Sir please making more videos on everycecuit

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