How

194

01:28:30

How does the1uOhm resistor draw current at 0V? Good question;)
Quantum electronics ;P

published 10 years ago

jonsiebott

10 years ago

The resistor at 1u ohm is so small as to be no different than a piece of wire and essentially drops no voltage. If the resistor is removed and a wire put in its place, you will see the same 18.1 mA of current.

UncleRick

10 years ago

The DVM figures (small purple voltage readings) are automatic and are limited to 3 significant figures, with no real auto ranging. The value of voltage must be under 0.00, therefore it does not get displayed. Example: 0.0005. We are left with doing the math ourselves.

Zafeirakis

10 years ago

Exactly... EC rounds the voltage to 0...In reality is nano Volts.

Zafeirakis

10 years ago

The smallest voltage EC can show is 1μV.

UncleRick

10 years ago

Not possible jonsiebott. You can not have current with 0 voltage drop. It is against the Law of Ohm. ;-)

UncleRick

10 years ago

Not quite, Zafeirakis. The DVM readings do not display anything below 10 millivolts. The scope is a different matter.

ETJAKEOC

10 years ago

Haha I found out quantum loop hole Rick ;)

UncleRick

10 years ago

If I had found it... I probably would have broken my ankle. :o) < clown relief.

thebugger

10 years ago

Yes the 1uohm resistor doesn't matter. It's like it's not there. Imagine the transistor as if though it's being directly grounded.

ETJAKEOC

10 years ago

Tsk tsk, but do the math, a voltage HAS to exist no matter how miniscule ;)

erikjohanson2003

8 years ago

I doubt that EC can stimulate quantum circuits!

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