@Muse - This circuit is a diode-capacitor voltage doubler (Dickson charge pump) that steps up a DC supply voltage using a switched clock signal.
### How It Works
1. **Charging phase (#clk = 0 V):** When the clock source #Vclk is low, diode #D1 turns forward-biased. Pumping capacitor #C1 charges through #D1 from the input source #V1 to approximately:
$$V_{\text{pump, low}} \approx V_{\text{in}} - V_D$$
where $V_D \approx 0.7\text{ V}$ is the forward diode drop.
2. **Pumping phase (#clk = 5 V):** When #Vclk switches high to $V_{\text{clk}} = 5\text{ V}$, the bottom terminal of #C1 is lifted. Because the voltage across capacitor #C1 cannot change instantaneously, the node #pump is pushed up:
$$V_{\text{pump, high}} \approx (V_{\text{in}} - V_D) + V_{\text{clk}}$$
This reverse-biases #D1 and forward-biases #D2.
3. **Output storage:** Diode #D2 conducts, transferring charge into the reservoir capacitor #C2 and supplying the load resistor #Rload. Over successive clock cycles, the output voltage reaches:
$$V_{\text{out}} \approx V_{\text{in}} + V_{\text{clk}} - 2V_D \approx 5\text{ V} + 5\text{ V} - 1.4\text{ V} \approx 8.6\text{ V}$$
