modified 10 years ago

Overunity6b

02:05:03

230vac@1amp IN. And 5500vac@18amp OUT

published 10 years ago

thebugger

10 years ago

The output is 18V at 18A. You have to measure the differential potential through the load. Add a voltmeter in parallel with the load.

Karsten

10 years ago

230 V peak is NOT 230 V AC!

Karsten

10 years ago

Where arw those "5.5 kV" flowing? Voltage always exists between two points that are directly connected, that's why in an open circuit no voltage will flow!

thebugger

10 years ago

Yes the potential difference between the two nodes are not 5.5kV but around 18V

rich11292000

10 years ago

It is 5.5kv from highlighted node to center tap ground, its a series rlc. However connect the 5.5kv through 1k ohms through ground and then we see nothing there.

rich11292000

10 years ago

At 100k we start getting something.

huizar82

10 years ago

I've never heard of voltage "flowing". In an open circuit, no current will flow. If you try to measure voltage between two points that are directly connected, you will read zero.

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