PNP transistors setup as a Darlington.

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01:49:13

Opposite of NPN you will add 0.7V across the Base Emitter junctions. This example has voltage Divider set to 6V. Then two base junctions so thats 0.7V x 2 = +1.4V added to the 6V which is 7.4V on the Emitter. Then VCC-Vb = 15-7.4 =  7.6V  V.E.C. 

published 4 years ago

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