Delay relay circuit with MOSFET. capacitor. resistor and relay

The time of delay determined by the capacity of capacitor. If you double the capacity you will get half frequency of delay. All that when the resistance of resistor is (1M ohm) . ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ [ Capacity(n) ==> Delay(n) ==> Frequency/n ] ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Ex: CAPACITY FREQUENCY DELAY 5uf :: 80mHZ = 12.5sec 10uf :: 40mHZ = 25sec 20uf :: 20mHZ = 50sec 40uf :: 10mHZ = 100sec 80uf :: 5mHZ = 200sec 160uf :: 2.5mHZ = 400sec 320uf :: 1.25mHZ = 800sec 640uf :: ~ 0.62mHZ = 1600sec 1280uf :: ~ 0.31mHZ = 3200sec 2560uf :: ~ 0.16mHZ = 6400sec 5120uf :: ~ 0.08mHZ = 12800sec 10240uf :: ~ 0.04mHZ = 25600sec 20480uf :: ~ 0.02mHZ = 51200sec . . . ....etc The same thing will be when you keep the capacity and change resistance. I HOPE YOU CAN UNDERSTAND WHAT I TALKING ABOUT . BECAUSE MY ENGLISH LANGUAGE IS NOT VERY GOOD.

published 8 years ago