Voltage x2

114

01:09:11

Multiplies voltage by two one diode charges the first capacitor to "source voltage"  the other diode doesn't conduct so the other capacitor is opened and doesn't interact.....  Now when the current is inverted the other diode#2 is "on",  the capacitor #1 was already charged so it ads up  with the source,  you can prove this with LVK theory  so now the second capacitor is charged by twice the voltage source 

published 10 years ago

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