Common Emitter amplifier

282

08:23:23

CE amplifier using 5 Vdc. 100mVpp input giving about 3 Vpp output.

published 6 years ago

hurz

6 years ago

suppose this is an audio amplifier the lower corner frequency should be 20Hz. Input resistance can be calculated 2.2k||hfe*470||10k=1.74kΩ with this resistance we can according to C=1/(2πfR) calculate the capacitor and get 4.58uF the next higher abailable is 4.7uF. Check the simulation it fits perfectly with the calcculation

johex

6 years ago

Thanks....duly noted.👍👍

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