it appears that the current thru the inductor briefly spikes just after the switch closes at t=0. It only lasts as long as is needed to go back to Steady-State after the addition of the left source to the circuit, roughly = 5/3 ms by guessing at the graph.
Yet, the calculated equation of the inductor current for t=>0 yields that
i (t=>0) = 0 Amps
for all values of t
Original problem:
conditions:
-switch opens at t=0
-the sources have been connected for a long time before the switch opens
Find i(t=>) of the inductor, if its current flows left to right.
I say that the inductor current @ t=0 and t--> infinity is 0A because there is never a closed circuit at those times.
That equation can't be right, can it?
