EE207HW83

it appears that the current thru the inductor briefly spikes just after the switch closes at t=0. It only lasts as long as is needed to go back to Steady-State after the addition of the left source to the circuit, roughly = 5/3 ms by guessing at the graph. Yet, the calculated equation of the inductor current for t=>0 yields that i (t=>0) = 0 Amps for all values of t Original problem: conditions: -switch opens at t=0 -the sources have been connected for a long time before the switch opens Find i(t=>) of the inductor, if its current flows left to right. I say that the inductor current @ t=0 and t--> infinity is 0A because there is never a closed circuit at those times. That equation can't be right, can it?

published 9 years ago