18 strong LEDs on 220V

152

02:45:23

This is how you can power 18 strong LEDs ( 5050 LEDs 60mA@3V)  from mains 220V@50Hz. The most expensive part is probably the capacitor of 5.8uF on 400V. These LEDs give around 20 lumens. 18 LEDs = 360 lumens which is the light power of incandescent light bulb of 25W. And here you burn only 6W. Resistors must be of 1/2W power.

published 9 years ago

yahyakassid

9 years ago

Cool

hurz

9 years ago

And what will happen if one row/led is dead? The lifetime of the left rows will dramatical decrease till selfdestruction!

GinkoBalboa

9 years ago

Not really. You can try and see that the current won't change a lot.

faceblast

9 years ago

nah he's right, there will be a couple of leds with lower Vf and these will die first. plus the first voltage spike on the mains will punch through the mains cap and send the whole thing live.

GinkoBalboa

9 years ago

Never hapened to me for a long time now. Maybe you re right, but on the end - nothing lasts forever 😊

hurz

9 years ago

All 6 string each 27.5mA ok till the first led is dead. With 5 strings 33mA for each. 4 strings 41.2mA ..... And so on ...

Robert_Kidd

9 years ago

Hurz is correct. You don't put LEDs in parallel without limiting resistors. Bad design.

hurz

9 years ago

And no problem to put leds in parrallel if Vf does match enough. However, you have to limit the voltage somehow to no selfdestruct them in long term.

GinkoBalboa

9 years ago

Ok I changed the circuit. Thank you hurz and Robert_Kidd.

Robert_Kidd

9 years ago

:-)

hurz

9 years ago

Never mind, but the problem is still the same. Anyway, if you are happy with this ... But check from time to time all rows are working if the last one is dead the capacitor gets 325V. So at least you should use 63V in case 5 rows are gone the voltage is already above 40V and the 100 Ohm resistor burns 10W

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