Transformerless led power supply help

U can calculate in simple way leds behave like zeners so they actualy can be considered as infinite resistance to voltage up to turn on point ant zero for volages above this point so due to this fact all voltage up tto turn on should be removed from calculus so u calculate peak current value u desire by use of ohm law equation where peak voltage is lowered by sum of turn on voltages of all diodes in series for example peak voltage for 230VAC is 325Vpp and u have 5 diodes for 2volts each so sum is 10 and substracted from peak value give 315 volts now u want for example 100mA peak current so u solve equation 100mA = 315v/xR so we write this xR= 315v /0,1A and u have required impedance value equal to Xc = 3150ohm so u take cap whose at rated frequency will have equivalent impedance of this value by use ordinary equation for cap impedance. U should calculate all for peak values cuz diodes are rated for DC current and when powered by cap through leo graetz bridge they will at rms values of current be overload cuz peak value wil, be higher about 0.4 times above calculated and even if diode can withstand short overcurents at low freqencies this overcurents will last much too long to be considered as short and can cause diode to pop after some time of normal operation (regards of their quality and if it is not overrated in currents handling already)

I,m not take a point that u use a 60hz/120VAC rms cuz not look into circ. But all is the same u simply take peak value of 120vac that is around 0.41 times higher than rms value s it will be around 170Vpp

Careful not to hurt the delicate grey matter Secu..

Thanks! That helped me be more confident in my calculations. Wasnt sure if I missed something. So (Vpeak - Vdrop) / Xc = peak current. Next question is my ac 0.5amps higher then my dc? This is happening to me when I hook it up on my bench.

AC peak values of curents and volages must be 0.41 times higher than equvalent root means sqare value (rms). And all multimeters measure AC in rms and all equipment powered from AC has rated voltages and currents also given for rms values. Why this rms is s so strange ?? Cuz AC is a problematic form of elcteicity. At peak value of 100 volts sine wave most of the time is below this value varying down up to zero .( time of zero power delivered) u to max 100 volts (max power point) so a rms was invented to overcome this. And it is translate in such way. A 100volts AC rms is AC sine wave voltage of such peak voltage magnitude that overal power delivered to load will became the same as u will use 100DC voltage with the same load ofcoz so it is simply a information that u are deal with AC whose can power ur bulb in same way as DC current of voltage equal of this number described as AC RMS . And this difference is a constant value for sine waves and mean that if u want to power something rated for 100rms AC u must set on for example power suply whose have voltage gauge for peak sine magnitude always a 0.41 higher than this 100volt . Thats why peak value of voltage in mains socktets is much higher than 110 or 230 v and hits a 180 and 325 volts respectively. Thats why u ned to pay attention to capacitors especialy those mkt/mkp nonpolarized ones as they frequently have values for max DC voltages so a rated 250v cap will not survive long time when used as vlotage dropper in transformerless power supply. Cap producers state that for AC a 400volt caps is absolute minimum. But there is also plenty of same type caps whose have voltage rated for AC voltages such as all X rated ones so this one with writen 250 volt can be safely used when directly plugged to mains wthout risk of short bbreakdown.

Thanks! Thus has helped tremendously. You should have been my electronics teacher for the first year lol