modified 9 years ago

Simple Low Power Ammeter

00:50:50

This ammeter displays load current in fraction of ammeter current. 

iL= iA*10^6.   

iL=load current, iA=ammeter current

it means that if ammeter current shows 1nA then load current is (10^-9)*(10^6)=10^-3 i.e. 1mA. You can change load resistance to see if you get correct reading.

published 9 years ago

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