I keep breaking it

104

01:44:08

Generates an Exavolt, Why does this happen to me?

published 5 years ago

jason9

5 years ago

An inductor acts like a short circuit to DC, so a lot of current flows. When the current in an inductor abruptly changes (like when you hit the button to instantly stop the very large current), it creates a large voltage, which ends up especially large due to the high quantity of current flowing. The 1:1000 ratio of the transformer multiplies that voltage by 1000 to create an even more extreme voltage.

fatcat2

5 years ago

That doesn't explain why it shorts 0V DC (a sine wave with 0V initially).

jason9

5 years ago

What do you mean?

Robert_Kidd

5 years ago

@AlejoA, put a 1K load across the output, wind the timebase to 1s/s, then see what it does.

fatcat2

5 years ago

I don't know why EC shows 'battery shorted' when a sine source with 0 degrees phase shift is connected to an inductor. Once the waveform starts, it shouldn't short out right?

Robert_Kidd

5 years ago

EC coils are ‘ideal’, that is they have no resistance. That’s what causes the message. Add a very small resistance in series with the coil to replicate real life.

schernya

5 years ago

@fatcat2 they add internal 0.1 Ohms resistor to the transformer's primary.

jason9

5 years ago

EC shows battery shorted when any voltage source is DC shorted, even if it has 0V DC.

fatcat2

5 years ago

Yup; that's what I meant. Dunno why, probably coz it cannot divide by zero?

jason9

5 years ago

Either that or simply not bothering to let 0V DC sources in particular be shorted.

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