modified 10 years ago

Help please.

02:57:04

I need help solving a problem, you can use any gate except buff gates and 3 switches, have only the light to light/the output to be true, when only one of the inputs are true, so can you help me?

published 10 years ago

MattFerrie

10 years ago

Use an XOR. XOR = (A and not B) or (B and not A)

the__one

10 years ago

((a XOR b) OR (a XOR c)) OR (b XOR c) - probably not the only or the most elegant solution, but should work if you have elements with 2 inputs.

the__one

10 years ago

Just try to imagine what your problem is step by step and you will see the solution. "I need A or B or C to be +, and not to be any pair of them +." (A or B or C) and !((A and B) or (A and C) or (B and C)) Please dont take this solution as granted, but I think it should also work. Defenetly you have more compact ones if you just take a minute to turn it around

MattFerrie

10 years ago

Karnaugh-map it!

roops1967

10 years ago

Got me thinking, ain't done that for awhile thanks! Posted a solution have a look

erikjohanson2003

10 years ago

http://everycircuit.com/circuit/6096169034317824

MmmAaaXxx

9 years ago

Nvm now, I solved it.

MmmAaaXxx

9 years ago

it's not (A XOR B) XOR C, that is also true if all inputs are true. it's complicated.

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