check transistor in dynamic mode

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00:47:28

base voltage 
Vb= Ve+Vbe 
 Vb= 9,41 V +1,35 V=10,76 V (± 0,1 V )

emitter voltage
Ve= Ic*Re   
  Ve=(465 mA X 20 ohms ) /1000
Ve = 9,30 V (± 0,11 V)

If Vc<Ve the transistor is saturated.
Vc=1,09V<Ve 9,41 V  transistor is saturated.

published 3 years ago

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