Op-Amp Integrator

289

09:42:23

An op-amp integrator produces an output proportional to the time integral of the input. In the classic inverting form, the signal passes through resistor Rin into the inverting node; a capacitor C from output to that node provides feedback, and the non-inverting input is grounded. Ideally, Vout/Vin = −1/(Rin C s), so vout(t) = −(1/(Rin C))∫vin(t)dt + V0. Because low-frequency gain is very high, DC offsets and bias currents can drive the output into saturation. Practical designs add a resistor Rf in parallel with C to limit DC gain and prevent drift, and choose op-amps with adequate bandwidth. You can modify the DC offset of the AC input to see this saturation in action. 

published 8 months ago

AdriZ

6 months ago

The opamp inputs are inverted (+ and - ) Here is a correction https://everycircuit.com/circuit/4809396710408192

add comment in editor

EveryCircuit is an easy to use, highly interactive circuit simulator and schematic capture tool. Real-time circuit simulation, interactivity, and dynamic visualization make it a must have application for professionals and academia. EveryCircuit user community has collaboratively created the largest searchable library of circuit designs. EveryCircuit app runs online in popular browsers and on mobile phones and tablets, enabling you to capture design ideas and learn electronics on the go.