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eroleken
modified 3 years ago

Voltage regulator

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6
327
05:49:57
Voltage regulator for 6.8 volt
published 3 years ago
Robert_Kidd
3 years ago
It will drop by about 0.7V when you apply a load.
eroleken
3 years ago
Then what is the role of transistor?
Robert_Kidd
3 years ago
Firstly, the voltmeter represents no load - it draws no current at all. In real life a voltmeter can have a very high impedance (resistance). In EC the voltmeter has infinite resistance since it’s model is a ‘perfect’ voltmeter.
Robert_Kidd
3 years ago
Without a load the transistor is doing very little since it’s emitter is floating (not connected to anything). When you apply a load the transistor will begin to conduct. When this occurs you have approx. 0.7V drop across the base emitter junction. It’s basically a PN diode junction.
Robert_Kidd
3 years ago
Note that in EC the base emitter drop is modelled at 0.8V rather than the more traditional text-book figure of 0.7V. This is a design decision taken by the app creators. If you apply a 1k load your 6.8V drops to 6.03V.
Robert_Kidd
3 years ago
If you want more details Google Series Pass Regulator.

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