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Filtro paso bajo 2 orden

@jairoliver1994
6 years ago
https://everycircuit.com/circuit/4977623997087744
DAtos de diseño: Q=0.7071 |H(0)|=1 f0=3KHz --> w0=18850 rad/s Fijar C1 = 100nF C2 = 10nF C1>>C2 para evitar la raíz negativa en R2 R1=R2/|H(0)| R3=1/(w0^2*R1*C1*C2) R2=(1/Q+-sqrt((1/Q)^2)-4*(|H(0)|+1)*C2/C1)/(2w0*C2)
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