modified 2 years ago

（Foward-active region）npn Bipolar Transistor

00:39:25

Forward-active region

The voltmeter voltage is controlled by the independent current source.

If the current source is 10uA (=0.7V), ammeter Ic = B*Ib. More precisely Vb > Ve (forward biased) and Vb < Vc (reversed biased).

Vb = Ic * Rc
       = 1mA * 1kohm
       = 1V
       = 1V (<10V)

Vce = Vc - Vb
       = 10V - 1V
       = 9V

Ic = Ib * B
    = 10uA * 100
    = 1mA

That's it, 10V input (independent voltage source) = 9V output (voltmeter) with Ic = 1mA.

Notice: 
1. Bad value: B = 100.

published 2 years ago

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