modified 11 years ago

Is it a band pass filter

01:56:57

How can i understand this circuit is band pass filter?

published 11 years ago

jreedx07

11 years ago

Theres a relation of the cut frecuency... 1/2π•R•C that will give you a frecuency. If you replace the inductor with a capacitor it will simplify calcs.. if you use the first cap and resistor with the relation above it will give a certain frecuency lets say 4hz tis means the capacitor will only let pass frecuency ABOVE 4hz while the other capacitor does the oposite only lets pass frecuency lower than established.... but still you need to make other changes in ur circuit or look for the relation having an inductance.... think its 1/2π[sqrt•LC]

Igor

11 years ago

Here is another way to think about this. At very low frequencies the inductor is a short, so output is zero. At very high frequencies the capacitor is a short, so output is zero. In between both have finite impedance, so output is higher.

jreedx07

11 years ago

Yes but u need a reference to know when and how will it be a short for a ciertan group of frecency

kyacn

11 years ago

Thanx a lot.. my teacher told this formulas but i couldnt understand. This time it will make sense :)

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