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hunar
modified 10 years ago

Why

3
5
137
01:44:39
What is the difference .. Why this is happening
published 10 years ago
alexbecker
10 years ago
Reduce the resistance of the base resistor, the transistor isn't saturated
jchmiel
10 years ago
Because some voltage is going from the collector to the base on the npn transistor that is above the load. It is also using more of the available power so there is less available to the load below. On the left your pulling to ground and most of the power is being used by the load vs the transistor.
Chryseus
10 years ago
The lamp on the right can have no more than 2.2V across it due to the base-emitter junction whereas the one on the left gets almost the full 3V, in addition 5k is a little too high, assuming the lamp draws 30mA at full brightness you want at least 1mA base current to ensure saturation, 2.2k being a good value, the lamp on the right has no need of a base resistor since the base current flows out the emitter so it will limit itself the resistor in this case is just dropping more voltage V = IR
hunar
10 years ago
Thank you all .. I got it
selman
10 years ago
I think it's like this, when you put a lamp which has a resistance 75Ohms at the emitter, what happens at the base is that this resistance gets larger by a factor of beta+1 which is about 7.5K, now this resistance appears in series with the 5K base resistance lowering the base current to ((3-0.85)/(5K+7.5K)) = 175uA and a collector current of 17mA which is no where near the full brightness, and lowering the 5k wont help scince the 7.5K is still there, even if you set the 5K to 0ohm the collector current will be only at 27mA

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