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Low Pass Order 3

@Carlos12001
1 year ago
https://everycircuit.com/circuit/4925765988384768
For a freq = 2 kHz, we use R = 600, imply C = 1/(2*pi*freq*R) = 132 nF DF1 = 1K/1K = 1 DF2 = 300/600 = 0.5
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