Calculating EMF

130

01:47:47

1.5v to 1.5kv 

Switch opened to 1.5 voltage source through (R1) 1ohm resistor = 1.5amps through L at T=infinity.
Switch opened to L. …Inductor acts as Voltage source, current at L = 1.5amps. Using ohms law 1.5amps through (R2) 1000ohm resistor A*R =1.5kv..  EMF…E= -L di/dt
1500v= -2di/dt
di/dt= -750 a/s

published 4 years ago

kiani

4 years ago

Put values to formulea, chk. Answers with EC measurment figures,, to make us believe.

JYounge

4 years ago

Hope I did it correctly…still new to this

kiani

4 years ago

Its a good start.. Since you have Dc. The the inductor charges up in similar fashion to a capacitor, with a time constant. {RC}, inductor time constant is L/R. Chk. This https://www.allaboutcircuits.com/textbook/direct-current/chpt-16/voltage-current-calculations/

JYounge

4 years ago

Will do thank you.

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