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02:39:24

R*2^0 = R1
R*2^1 = R2
R*2^2 = R3
R*2^3 = R4

Using the first operational amplifier, we sum with an inverting summer. After that we turn the sign with an inverter. Everything before is self-explanatory. The lamp shows the analog value.

published 4 years ago

rjiQaher

4 years ago

Great

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