modified 9 years ago

Ohms Law Protecting 2 Low-Voltage LEDs On Mains

01:06:37

Set at the current limit of the LEDs of 20mA with a 5.9K resistor (-0.1 Ohms to compensate for the resistance of the LED leads).

published 9 years ago

BillyT

9 years ago

120V RMS = 169.68V Peak. Resistor for 20mA = 8.5k, Wattage required = approximately 4W. Nearest E24 resistor value = 9.1k. Nearest standard Wattage value 5W. Safety Factor = NILL.

Khombhat

9 years ago

I did not think that EC accounted for RMS. Anyway, this is clearly not a practical circuit and would like not work with real mains, as it is, but this is merely a tool I sometimes use to demonstrate Ohm's Law to people who do not yet understand the relationship between V, I, and R. Gotta start somewhere! Thanks for your feedback, though!

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